A change of 8 . 0 mA in the emitter current brings a change of 7 . 9 mA in the collector current. The values of α a n d β are

Step-by-step solution

Given that, change in emitter current, ∆ I E = 8 mA and change in collector current, ∆ I C = 7.9 mA We know that, α = ∆ I C ∆ I E ⇒ = 7.9 8 ⇒ α ≈ 0.99 Also, we know that β = α 1 - α ⇒ = 7.9 8 1 - 7.9 8 = 7.9 8 - 7.9 Or β = 7.9 0.1 = 79 Hence, the required answer is α = 0.99 and β = 79 .