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A particular semiconductor in equilibrium has 1 × 10 16 cm - 3 donor atoms, 1 . 1 × 10 17 cm - 3 acceptor atoms. If the intrinsic carrier density n i of the semiconductor is 10 12 cm - 3 , then the electron density in it will be

Options

  1. A10 16   cm - 3
  2. B10 12   cm - 3
  3. C1.1 × 10 17   cm - 3
  4. D10 7   cm - 3

Correct answer

D. 10 7   cm - 3

Step-by-step solution

From mass action law, n e n h = n i 2 and n h = 1.1 × 10 17 - 10 16   cm - 3 =   10 17   cm - 3 ∴         n e = 10 12 2 10 17 = 10 7   cm - 3

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