NTA Abhyas JEE Main2020PhysicsSemiconductorsPractice
The DC common-emitter current gain of an n-p-n transistor is 50 . The potential difference applied across the collector and emitter of a transistor used in CE configuration is, V C E = 2 V . If the collector resistance R C = 4 k Ω , the base current I B and the collector current I C are
Options
- AI B = 1 0 μ A , I C = 0.5 m A
- BI B = 0. 5 μ A , I C = 10 m A
- CI B = 5  μ A ,   I C = 1  m A
- DI B = 1 μ A ,I C = 0.5 ;m A
Correct answer
A. I B = 1 0 μ A , I C = 0.5 m A
Step-by-step solution
Given, β = 50 , V C E = 2 V , R c = 4 k Ω I C = V C E R C = 2 4 × 10 3 = 5 × 10 - 4 A I C = 0.5 mA DC current gain, β = I C I B I B = I C β = 0.5 × 10 - 3 50 = 10 - 5 A Hence, I B = 10 μA