For an amplitude modulated wave, the maximum amplitude is found to be 10 V while the minimum amplitude is found to be 2 V. The modulation index is

Step-by-step solution

Given, maximum amplitude A max = 10 V Minimum amplitude A min = 2 V Let A c and A m be the amplitudes of carrier wave and signal wave ∴ A max = A c + A m = 10 ...(i) and A min = A c – A m = 2 ...(i) Adding the Eqs. (i) and (ii), we get 2A c = 12 or A c = 6 V and A m = 10 – 6 = 4 V μ = A m A c = 4 6 = 2 3