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A Zener diode is connected to a battery and a load as shown below: The currents I, I Z and I L are respectively

Options

  1. A12.5 mA, 7.5 mA, 5 mA
  2. B15 mA, 7.5 mA, 7.5 mA
  3. C12.5 mA, 5 mA, 7.5 mA
  4. D15 mA, 5 mA, 10 mA

Correct answer

A. 12.5 mA, 7.5 mA, 5 mA

Step-by-step solution

I L = V AB R L = 1 0 2 0 0 0 = 5 mA I = 6 0 - 1 0 4 0 0 0 = 5 0 4 0 0 0 = 1 2 · 5 mA I = I L + I Z ∴ I Z = I - I L = 7 · 5 mA Hence, 12.5 mA, 7.5 mA, 5 mA

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