The potential difference across a resistor is measured to be V = ( 8 ± 0.5 ) V and the current through it is measured to be I = ( 2 ± 0.2 ) A , then the value of the resistance R is

Correct answer: A. 4 ± 16.25% V = ( 8 + 0.5 ) I = ( 2 + 0.2 ) R = (8)/(2) = 4 (∆ R)/(R)% = ((∆ V)/(V) + (∆ I)/(I)) = ((0.5)/(8) + (0.2)/(2)) ×100 = 16.25% ∴ R = ( 4 ± 16.25% )

NTA Abhyas 2020

Exam: NTA Abhyas
Year: 2020
Subject: Physics
Chapter: Units and Dimensions

NTA Abhyas 2020 · Physics · Units and Dimensions

The potential difference across a resistor is measured to be V = (...

The potential difference across a resistor is measured to be

V = ( 8 \pm 0.5 ) V

and the current through it is measured to be

I = ( 2 \pm 0.2 ) A

, then the value of the resistance

R

Options

A $4 \pm 16.25%$
B $4 \pm 6.25%$
C $4 \pm 10%$
D $4 \pm 8%$

Correct answer

A. $4 \pm 16.25%$

Step-by-step solution

V = ( 8 + 0.5 )

<br/><br/>

I = ( 2 + 0.2 )

<br/><br/>

R = \dfrac{8}{2} = 4

<br/><br/>

\dfrac{∆ R}{R}% = \left(\dfrac{∆ V}{V} + \dfrac{∆ I}{I}\right)

= \left(\dfrac{0.5}{8} + \dfrac{0.2}{2}\right) \times100 = 16.25%

∴ R = ( 4

\pm

16.25% )

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