NTA Abhyas JEE Main2020PhysicsUnits and DimensionsPractice
In the formula, a = 3 b c 2 , a and c have dimensions of electric capacitance and magnetic field intensity respectively. The dimensions of b in S . I . system are
Options
- A[ M - 3 L - 2 T 4 Q 4 ]
- B[ M - 3 T 4 Q 4 ]
- C[ M - 3 T 3 Q ]
- D[ M - 3 L 2 T 4 Q - 4 ]
Correct answer
A. [ M - 3 L - 2 T 4 Q 4 ]
Step-by-step solution
Given, a = 3 b c 2 ⇒ b = a 3 c 2 Writing dimensions for a and c , we have b = Q / V B 2 = Q [ M L 2 T - 2 Q - 1 ] - 1 M T - 1 Q - 1 2 = [ M - 3 L - 2 T 4 Q 4 ]