NTA Abhyas JEE Main2020PhysicsUnits and DimensionsPractice
If speed V , force F and acceleration a are chosen as the fundamental physical quantities, then the dimension of Young's modulus in terms of V , F and a are
Options
- AV - 3 Fa
- BV - 4 F 2 a 2
- CV - 4 Fa 2
- DV - 4 F 2 a
Correct answer
C. V - 4 Fa 2
Step-by-step solution
Let Y = f V ,   F ,   a ∴ Y = KV x F y a z ,             K → Unitless ∴ Y = V x F y a z ∴ ML - 1 T - 2 = LT - 1 x MLT - 2 y LT - 2 z ∴ M L - 1 = T - 2 =   M y L x + y + z T - x - 2 y - 2 z   ∴ y = 1 ;         x + y + z = - 1 ;         - x - 2 y - 2 z = 2 ∴ x + z = - 2                       ∴ x + 2 y + 2 z = 2 ∴ x + 2 z