NTA Abhyas JEE Main2020PhysicsUnits and DimensionsPractice
Dimensions of permeability ( μ 0 ) are
Options
- AA − 2 M 1 L 1 T − 2
- BM L T − 2
- CM L 0 T − 1
- DA − 1 M L T 2
Correct answer
A. A − 2 M 1 L 1 T − 2
Step-by-step solution
F = μ 0 4 π 2 I 1 I 2 l r ⇒ μ 0 = [ F ] [ A ] − 2 = [ M L T − 2 A − 2 ]