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NTA Abhyas JEE Main2020PhysicsUnits and DimensionsPractice

Find the dimensions of electric permittivity

Options

  1. AA 2 M - 1 L - 3 T 4
  2. BA 2 M - 1 L - 3 T 0
  3. CA M - 1 L - 3 T 4
  4. DA 2 M 0 L - 3 T 4

Correct answer

A. A 2 M - 1 L - 3 T 4

Step-by-step solution

From Coulomb's law, the force of attraction/repulsion between two point charges q and q separated by distance r is                                           F = 1 4 π ε 0 q 2 r 2 ⇒                               ε 0 = 1 4 π   . q 2 F r 2 Where ε 0 is electric permittivity. Dimensions of ε 0 = A

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