Find the dimensions of electric permittivity

From Coulomb's law, the force of attraction/repulsion between two point charges $q and q$ separated by distance $r$ is

$F = \dfrac{1}{4\pi{ε}_{0}}\dfrac{q^{2}}{r^{2}}$

$⇒ {ε}_{0} = \dfrac{1}{4\pi}. \dfrac{q^{2}}{Fr^{2}}$

Where ${ε}_{0}$ is electric permittivity.

Dimensions of ${ε}_{0} = \dfrac{{ \left[AT\right]}^{2}}{ \left[MLT^{- 2}\right] \left[L^{2}\right]}$

\left[{ε}_{0}\right] =\left[A^{2}M^{- 1}L^{- 3}T^{4}\right]