NTA Abhyas JEE Main2020PhysicsUnits and DimensionsPractice
The focal length of a mirror is given by 1 f = 1 u + 1 v where u and v represent object and image distances respectively. The maximum relative error in f is
Options
- A∆ f f = ∆ u u + ∆ v v
- B∆ f f = ∆ u u + ∆ v v - ∆ u + v u + v
- C∆ f f = ∆ u u + ∆ v v - ∆ u - v u + v
- D∆ f f = ∆ u u + ∆ v v + ∆ u u + v + ∆ v u + v
Correct answer
D. ∆ f f = ∆ u u + ∆ v v + ∆ u u + v + ∆ v u + v
Step-by-step solution
f = u v u + v , ∆ f f = ∆ u u + ∆ v v + Δ( u + v ) u + v