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The main scale of a Vernier Callipers reads in millimeter and its vernier is divided into 10 divisions which coincides with 9 divisions of the main scale. The length of the object for situation is found to be m m . Find the value of x .

Correct answer

5.20

Step-by-step solution

List count = 0.1 m m Negative zero error = L C × 10 - 9 = 0.1 m m Measured value = 5.0 + L C × 1 + negative Zero error = 5.20

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