NTA Abhyas JEE Main2020PhysicsUnits and DimensionsPractice
Force acting on a particle is given by F = A - x B t , where x is in metre and t is in seconds. The dimensions of B is -
Options
- AM L T - 2
- BM - 1 T - 3
- CM - 1 T
- DM T - 1
Correct answer
C. M - 1 T
Step-by-step solution
F = ma, we get F = M 1   [ L 1 T - 2 ] The dimension of force = [ MLT - 2 ] F = A - x B t B = [ L ] M L T - 2 [ T ] = M - 1 T 1