NTA Abhyas JEE Main2020PhysicsUnits and DimensionsPractice
F = α β e - x α k t k = Boltzmann constant t = temperature x = distance The dimensions of β is
Options
- AM   L   T - 4
- BM - 2   L - 2   T 4
- CM   L   T - 2
- DM 2   L   T - 1
Correct answer
B. M - 2   L - 2   T 4
Step-by-step solution
F = α β e - x α K T x α = ML 2 T - 2 α = M - 1 L - 1 T - 2 MLT - 2 = M - 1 L - 1 T 2 β - 1 β = M - 2   L - 2   T 4