NTA Abhyas JEE Main2020PhysicsUnits and DimensionsPractice
If pressure P , velocity V and time T are taken as fundamental physical quantities, the dimensional formula of force is
Options
- AP V 2 T 2
- BP − 1 V 2 T − 2
- CP V T 2
- DP − 1 V T 2
Correct answer
A. P V 2 T 2
Step-by-step solution
Let F ∝ P x V y T z by substituting the following dimensions : [ P ] = [ M L − 1 T − 2 ] [ V ] = [ L T − 1 ] , [ T ] = [ T ] and comparing the dimension of both sides x = 1 , y = 2 , z = 2 , so F = P V 2 T 2