NTA Abhyas JEE Main2020PhysicsUnits and DimensionsPractice
Position of a body with acceleration a is given by x = k a m t n . Here t is time. Find the dimensions of m and n .
Options
- Am = 1 , n = 1
- Bm = 1 , n = 2
- Cm = 2 , n = 1
- Dm = 2 , n = 2
Correct answer
B. m = 1 , n = 2
Step-by-step solution
Positions x = k a m t n M 0 L T 0 = L T - 2 m T n = M 0 L m T - 2 m + n On comparing both sides m = 1 - 2 m + n = 0 n = 2 m n = 2 × 1 = 2