NTA Abhyas JEE Main2020PhysicsUnits and DimensionsPractice
Time T , velocity C and angular momentum h are chosen as fundamental quantities instead of mass, length and time. In terms of these, the dimensions of mass would be:
Options
- AM = T - 1 C - 2 h
- B[ M ] = [ T − 1 C 2 h ]
- CM = T - 1 C - 2 h - 1
- D[ M ] = [ TC − 2 h ]
Correct answer
A. M = T - 1 C - 2 h
Step-by-step solution
M ∝ T x C y h z M 1 L 0 T 0 = T 1 x L 1 T - 1 y M 1 L 2 T - 1 z [ M 1   L 0 T 0 ] =[ M z   L y + 2 z T x - y - z ] ⟹ z = 1 y + 2 z = 0 , x - y - z = 0 solving y = - 2 and x = - 1 M    ⇒      T - 1   C - 2   h 1