If speed V , acceleration A and force F are considered as fundamental units, the dimension of Young's modulus will be:

Step-by-step solution

Let Y = f V ,   F ,   A Y = K V x F y A z ,   K → Unit less Y = V x F y A z ML - 1 T - 2 = LT - 1 x MLT - 2 y LT - 2 z M L - 1 T - 2 = M y L x + y + z T - x - 2 y - 2 z ⇒     y = 1 ,   x + y + z = - 1 ;   - x - 2 y - 2 z = - 2 x + z = - 2     x + 2 y + 2 z = 2 z = 2 ,   x = - 4     x + 2 z = 0 Y = V - 4 A 2 F