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AP EAMCET202422 May 2024Evening ShiftMathematicsInverse Trigonometric FunctionsActual

( _ n=1 ⁵⁰ ⁻¹ ( 1 1+n+n^2 ) )=

Options

  1. A26 25
  2. B25 26
  3. C50 51
  4. D52 51

Correct answer

A. 26 25

Step-by-step solution

aligned & ( _ n=1 ⁵⁰ ⁻¹ ( 1 1+n+n^2 ) ) = & ( _ n=1 ⁵⁰ ⁻¹ ( n+1-n 1+(n+1) n ) ) = & ( _ n=1 ⁵⁰ ( ⁻¹(n+1)- ⁻¹ n ) ) = & ( ⁻¹ 51- ⁻¹ 1 )= ( ⁻¹ 51-1 1+51 ) = & ( ⁻¹ 52 50 )= 52 50 = 26 25 aligned

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