NTA Abhyas JEE Main2020PhysicsWork, Power and EnergyPractice
The velocity-time graph of a particle of mass 10 kg is shown in the figure. The net work done on the particle in the first two seconds of the motion is
Options
- A- 9300 J
- B12000 J
- C- 4500 J
- D- 12000 J
Correct answer
C. - 4500 J
Step-by-step solution
v = - 5 t + 50 v a t t = 2 = 40 ∆ K . E . = W . D . = 1 2 40 2 - 50 2 × 10 = - 4500 J