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AP EAMCET202421 May 2024Evening ShiftMathematicsInverse Trigonometric FunctionsActual

2 coth h⁻¹(4)+ h⁻¹ ( 3 5 )=

Options

  1. A5
  2. B2 3
  3. C3 2
  4. D5 3

Correct answer

A. 5

Step-by-step solution

As h⁻¹(x)= 1 2 ( x+1 x-1 ) and h⁻¹(x)= ( 1+ 1-x^2 x ) Now, 2 h⁻¹(4)+ h⁻¹ ( 3 5 ) = ( 4+1 4-1 )+ ( 1+ 1- 9 25 3 5 )= 5 3 + 3= 5

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