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NTA Abhyas JEE Main2020PhysicsWork, Power and EnergyPractice

The work done by the force F → = 6 i ^ + 2 j ^ N in displacing an object from r 1 → = 3 i ^ + 8 j ^ m to r 2 → = 5 i ^ − 4 j ^ m , is

Options

  1. A12   J
  2. B- 36   J
  3. C36   J
  4. D- 12   J

Correct answer

D. - 12   J

Step-by-step solution

F → = 6 i ^ + 2 j ^ r → = r → 2 - r → 1 = 5 i ^ - 4 j ^ - 3 i ^ - 8 j ^ = 2 i ^ - 12 j ^ W = F → · S → = ( 6 i ^ + 2 j ^ ) · ( 2 i ^ - 12 j ^ ) = - 12 J

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