NTA Abhyas JEE Main2020PhysicsWork, Power and EnergyPractice
10 22 gas molecules each of mass 10 - 26 kg collide with a surface (perpendicular to it) elastically per second over an area 1 m 2 with a speed of 10 4 m s - 1 . The pressure exerted by the gas molecules will be
Options
- A2   N  m - 2
- B4   N  m - 2
- C8   N  m - 2
- D16   N  m - 2
Correct answer
A. 2   N  m - 2
Step-by-step solution
v = 10 4   m   s - 1 m = 10 - 26 n = 10 22 A = 1   m 2 Δp = 2 mnv Δp = 2 × 10 22 × 10 - 26 × 10 4 = 2 P = F A = 2   N   m - 2