NTA Abhyas JEE Main2020PhysicsWork, Power and EnergyPractice
A particle is placed at the origin and a force F = kx is acting on it (where k is a positive constant). IF U ( 0 ) = 0 , the graph of U ( x ) versus x will be (where U is the potential energy function)
Correct answer
0
Step-by-step solution
F = - dU dx ⇒ ∫ dU = - ∫ Fdx U 2 - U 1 = - ∫ kxdx ⇒ U = - 1 2 kx 2