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NTA Abhyas JEE Main2020PhysicsWork, Power and EnergyPractice

A particle starts with speed v 0 from x = 0 along x -axis with retardation proportional to the square of its displacement. Work done by the force acting on the particle is proportional to

Options

  1. Ax 5 2
  2. Bx 3
  3. Ce x
  4. Dx 2

Correct answer

B. x 3

Step-by-step solution

Given a = - Kx 2 or – v dv dx = x 2 integrating both sides – 1 2 v 2 – v 0 2 = x 3 3 Now, using work-energy theorem W = ∆ KE W   ∝   x 3

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