NTA Abhyas JEE Main2020PhysicsWork, Power and EnergyPractice
Two particles of masses m 1 and m 2 are initially at rest at an infinite distance apart. If they approach each other under their mutual interaction given by F = - K r 2 . Their speed of approach at the instant when they are at a distance d apart is
Options
- A2 K d 1 m 1 + 1 m 2
- B2 K d 1 m 1 - 1 m 2
- C2 K d m 1 m 2 m 1 + m 2
- D2 K d m 1 m 2 m 1 - m 2
Correct answer
A. 2 K d 1 m 1 + 1 m 2
Step-by-step solution
Let μ be the reduced mass of the system and v be the approach speed of the particles, then 1 2 μv 2 = ∫ ∞ d F → . d r → ⇒ 1 2 m 1 m 2 m 1 + m 2 v 2 = - ∫ ∞ d K r 2 dr ∴ v = 2 K d 1 m 1 + 1 m 2