NTA Abhyas JEE Main2020PhysicsWork, Power and EnergyPractice
Two spherical bodies of the same mass M , are moving with velocities v 1 and v 2 respectively, along the same line. These bodies collide perfectly inelastically and head-on. The loss in kinetic energy is
Options
- A1 2 M ( v 1 - v 2 )
- B1 2 M ( v 1 2 - v 2 2 )
- C1 4 M v 1 - v 2 2
- D2 M ( v 1 2 - v 2 2 )
Correct answer
C. 1 4 M v 1 - v 2 2
Step-by-step solution
Loss of kinetic energy = 1 2 m 1 m 2 m 1 + m 2 v 1 - v 2 2 = 1 2 × M × M M + M v 1 - v 2 2 = M ⋅ M 2 2 M v 1 - v 2 2 = M 4 ( v 1 - v 2 ) 2