A wire, suspended vertically from one of its ends, is stretched by attaching a weight of 200 N to the lower end. The weight stretches the wire by 1 m m . The elastic energy (in J ) stored in the wire is

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Quantrex Academy · Accepted Answer

Correct answer: 0.1

U = 1 2 × F × l = 1 2 × 200 × 10 - 3 = 0.1 J

A wire, suspended vertically from one of its ends, is stretched by attaching a weight of 200 N to the lower end. The weight stretches the wire by 1 m m . The elastic energy (in J ) stored in the wire is

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