NTA Abhyas JEE Main2020PhysicsWork, Power and EnergyPractice
Initially, a block of mass m is at rest on a frictionless floor and the spring is in a relaxed condition. One end of the spring is rigidly attached to the block and the other end is fixed to a wall. A constant force is applied on the block as shown in the figure. The maximum velocity of the block is
Options
- AF m K
- BF 2 m K
- CF 2 m K
- D2 F m K
Correct answer
A. F m K
Step-by-step solution
The block attains maximum speed when it passes through its equilibrium position. F = K x x = F K From work-energy theorem - 1 2   K   K F 2 + F F K = 1 2 m v m a x 2 F 2 2 K = 1 2 m v m a x 2 v m a x = F m K