Quantrex Quantrex AcademyJEE · NEET · NDA PYQs with solutions Open app
NTA Abhyas JEE Main2020PhysicsWork, Power and EnergyPractice

An object of mass 8 kg starts to move from rest under the action of a variable force F = 3 x N where x is the distance (in m ) covered by the object. If initially, the position of the object is x = 2 m , then find its speed (in m s - 1 ) when it crosses x = 10 m .

Correct answer

6

Step-by-step solution

Increment in kinetic energy = work done 1 2 m v 2 - u 2 = ∫ x 1 x 2 F . d x = ∫ 2 10 3 x   d x 1 2 m v 2 = 3 2 x 2 2 10 = 3 2 100 - 4 1 2 × 8 × v 2 = 3 2 × 96 v = 6   m   s - 1

Practice Work, Power and Energy on Quantrex Academy →

More from Work, Power and Energy

All Work, Power and Energy questions Full Work, Power and Energy list All NTA Abhyas JEE Main PYQs