NTA Abhyas JEE Main2020PhysicsWork, Power and EnergyPractice
A particle moves with a velocity of 4 i ^ − 2 j ^ + 2 k ^ m s - 1 under the influence of a constant force F → = 10 i ^ + 3 j ^ - 2 k ^ N . The instantaneous power applied to the particle is
Correct answer
30
Step-by-step solution
P = F → ⋅ v → = 4 i ^ - 2 j ^ + 2 k ^ · 10 i ^ + 3 j ^ - 2 k ^ = 40 - 6 - 4 ∴ P = 30  W