NTA Abhyas JEE Main2020PhysicsWork, Power and EnergyPractice
The potential energy of a particle under a conservative force is given by U x = x 2 - 3 x J . The equilibrium position of the particle is at x m . The value of 10 x will be
Correct answer
15
Step-by-step solution
U x = x 2 − 3 x J For a conservative field, Force, F = - d U d x ∴ F = - d d x x 2 - 3 x = - 2 x - 3 = - 2 x + 3 At equilibrium position, F = 0 - 2 x + 3 = 0 ⇒ x = 3 2 m = 1 · 5 m