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NTA Abhyas JEE Main2020PhysicsWork, Power and EnergyPractice

The potential energy of a particle under a conservative force is given by U x = x 2 - 3 x J . The equilibrium position of the particle is at x m . The value of 10 x will be

Correct answer

15

Step-by-step solution

U x = x 2 − 3 x J For a conservative field, Force, F ⁡ = - d ⁡ U ⁡ d ⁡ x ∴ F ⁡ = - d ⁡ d ⁡ x x 2 - 3 x = - 2 x - 3 = - 2 x + 3 At equilibrium position, F = 0 - 2 x + 3 = 0 ⇒ x = 3 2 m ⁡ = 1 · 5 m

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