Quantrex Quantrex AcademyJEE · NEET · NDA PYQs with solutions Open app
NTA Abhyas JEE Main2020PhysicsWork, Power and EnergyPractice

A force F is related to the position of a particle by the relation F = ( 10 x 2 ) N . The work done by the force when the particle moves from x = 2 m to x = 4 m is

Options

  1. A5 6 3 J
  2. B560   J
  3. C5 6 0 3   J
  4. D3 5 6 0 J

Correct answer

C. 5 6 0 3   J

Step-by-step solution

W = ∫ 2 4 Fdx = ∫ 2 4 10 x 2 d ⁡ x = 10 x 3 3 2 4 = 1 0 3 4 3 - 2 3 = 1 0 3 × 5 6 = 5 6 0 3    J

Practice Work, Power and Energy on Quantrex Academy →

More from Work, Power and Energy

All Work, Power and Energy questions Full Work, Power and Energy list All NTA Abhyas JEE Main PYQs