Quantrex Quantrex AcademyJEE · NEET · NDA PYQs with solutions Open app
NTA Abhyas JEE Main2020PhysicsWork, Power and EnergyPractice

The block of mass 'm' initially at x = 0 is acted upon by a horizontal force F = a - bx as shown in the figure. The coefficient of friction between the surfaces of contact is μ . The net work done on the block is zero if the block travels a distance of ________.

Options

  1. Aa - μ mg / 2 b
  2. Ba - μ mg / b
  3. C2 a - μ mg / b
  4. Da - 2 μ mg / b

Correct answer

C. 2 a - μ mg / b

Step-by-step solution

f = a - bx f n ef = a - bx - f s For block to move at x = 0 a - b x > f s max = μ mg a > μ mg , So we are assuming motion starts at x = 0 w = ∫ a - bx - μ mg dx o = ax - bx 2 2 - μ mgx ⇒ x a - bx 2 - μ mg = 0 x = 0 a - bx 2 - μ mg = 0 bx 2 = a - μ mg x = 2 b a - μ mg

Practice Work, Power and Energy on Quantrex Academy →

More from Work, Power and Energy

All Work, Power and Energy questions Full Work, Power and Energy list All NTA Abhyas JEE Main PYQs