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NTA Abhyas JEE Main2020PhysicsWork, Power and EnergyPractice

A particle is projected vertically upwards with a speed of 16 m s - 1 , after some time, when it again passes through the point of projection, its speed is found to be 8 m s - 1 . It is known that the work done by air resistance is the same during upward and downward motion. Then the maximum height attained by the particle is (Take g = 10 m s - 2 ) :

Options

  1. A8 m
  2. B4.8 m
  3. C17.6 m
  4. D12.8 m

Correct answer

A. 8 m

Step-by-step solution

From work-energy theorem For upward motion 1 2 m 1 6 2 = mgh + W (work by air resistance) For downward motion 1 2 m 8 2 = mgh - W ⇒ 1 2 1 6 2 + 8 2 = 2 gh or h = 8   m

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