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NTA Abhyas JEE Main2020PhysicsWork, Power and EnergyPractice

The potential energy for a force field F → is given by U ( x , y ) = cos ( x + y ) . The force acting on a particle at the position given by coordinates 0 , π / 4 is

Options

  1. A- 1 2 i ^ + j ^
  2. B1 2 i ^ + j ^
  3. C1 2 i ^ + 3 2 j ^
  4. D1 2 i ^ - 3 2 j ^

Correct answer

B. 1 2 i ^ + j ^

Step-by-step solution

F x = - ∂ U ∂ x = sin x + y , F y = - ∂ U ∂ x = sin x + y F x = sin x + y ] 0 , π / 4 = 1 2 , F y = sin x + y ] 0 , π / 4 = 1 2 ∴ F = 1 2 i ^ + j ^

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