NTA Abhyas JEE Main2020PhysicsWork, Power and EnergyPractice
The potential energy for a force field F → is given by U ( x , y ) = cos ( x + y ) . The force acting on a particle at the position given by coordinates 0 , π / 4 is
Options
- A- 1 2 i ^ + j ^
- B1 2 i ^ + j ^
- C1 2 i ^ + 3 2 j ^
- D1 2 i ^ - 3 2 j ^
Correct answer
B. 1 2 i ^ + j ^
Step-by-step solution
F x = - ∂ U ∂ x = sin x + y , F y = - ∂ U ∂ x = sin x + y F x = sin x + y ] 0 , π / 4 = 1 2 , F y = sin x + y ] 0 , π / 4 = 1 2 ∴ F = 1 2 i ^ + j ^