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NTA Abhyas JEE Main2020PhysicsWork, Power and EnergyPractice

A uniform chain of length L and mass M is lying on a smooth table and one-third of its length is hanging vertically down over the edge of the table. If g is the acceleration due to gravity, the work required to pull the hanging part on to the table is

Options

  1. AM g L
  2. BM g L 3
  3. CM g L 9
  4. DM g L 18

Correct answer

D. M g L 18

Step-by-step solution

Mass of hanging portion is M 3 h = L 6 below the table top. Therefore, the required work done is, W = m g h = M 3 ( g ) L 6 = M g L 18

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