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AP EAMCET202422 May 2024Morning ShiftMathematicsLimitsActual

_ x 0 [ 1 x - 1 e^x-1 ]=

Options

  1. A0
  2. B1
  3. C2
  4. D1 2

Correct answer

D. 1 2

Step-by-step solution

_ x 0 [ 1 x - 1 e^x-1 ]= _ x 0 [ e^x-1-x x e^x-x ] [ 0 0 form ] Applying L's Hopital rule = _ x 0 [ e^x-1 x e^x+e^x-1 ] [ 0 0 form ] Applying L's Hopital rule = _ x 0 [ e^x x e^x+2 e^x ]= 1 2

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