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AP EAMCET202316 May 2023Morning ShiftMathematicsLimitsActual

_ n 1 n ( 1 e^ 1 / n + 1 e^ 2 / n + 1 e^ 3 / n + + 1 e^2 )=

Options

  1. A1- e ⁻²
  2. B1+ e ⁻²
  3. Ce ^2-1
  4. De ^2+1

Correct answer

A. 1- e ⁻²

Step-by-step solution

_ h 1 n ( 1 e^ 1 / n + 1 e^ 2 / n + 1 e^ 3 / n + .+ 1 e^2 )= _ h 1 n _ k=1 ^ 2 n 1 e^ k / n aligned & = ₀^2 1 e^x d x= ₀^2 e^ -x d x= [-e^ -x ]₀^2 & =-e⁻²+e^0=1-e⁻² aligned

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