AP EAMCET20225 Jul 2022Evening ShiftMathematicsLimitsActual
_ n A+e^ n x x+A e^ n x =
Options
- AA x , when x < 0
- B1 , when x >0
- C0 , when x R
- DA , when x=0
Correct answer
A. A x , when x < 0
Step-by-step solution
when x < 0 aligned & n x < 0 & _ n n x - & _ n e^ n x =e^ - =0 aligned _ n A+e^ n x x+A e^ n x = _ n A+0 x+A 0 = A x