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AP EAMCET20225 Jul 2022Morning ShiftMathematicsLimitsActual

_ x - 3|x|-x |x|-2 x - _ x 0 (1+x^3 ) ^3 x =

Options

  1. A1 3
  2. B- 1 4
  3. C2
  4. D- 5 3

Correct answer

A. 1 3

Step-by-step solution

_ x - 3|x|-x |x|-2 x - _ x 0 (1+x^3 ) ^3 x _ x - -3 x-x -x-2 x - _ x 0 (1+x^3 ) x^3 ( x^3 x ) x^3 _ x - -4 x -3 x - _ x 0 1 ( ^3 x x^3 ) _ x - 4 3 -1= 1 3

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