AP EAMCET20224 Jul 2022Evening ShiftMathematicsLimitsActual
If l , m l < m are roots of a x 2 + b x + c = 0 , then lim x → a a x 2 + b x + c a x 2 + b x + c =
Options
- Aa a , ∀ a ∈ R
- B- a a , when α ∉ l , m
- C- a a , when α ∈ l , m
- Da a , α ∈ l , m
Correct answer
C. - a a , when α ∈ l , m
Step-by-step solution
Given, l ,   m l < m are roots of a x 2 + b x + c = 0 , Also we know that value of function between the roots is negative or positive depending upon the value of a , So, when x ∈ l , m then f x = a x 2 + b x + c < 0 ,   if   a > 0 and f x = a x 2 + b x + c > 0 ,   if   a < 0 So now using the above concept we will solve the given limit, lim x → α a x 2 + b x + c a x 2 + b x + c = - a a , when α ∈ l , m