AP EAMCET20224 Jul 2022Morning ShiftMathematicsLimitsActual
If lim x → 0 x x 4 + 4 x 2 + 5 = k , lim x → 0 x 4 sin 1 3 x = l , Then k + l =
Options
- A0
- B1
- C- 1
- D5
Correct answer
A. 0
Step-by-step solution
Given, lim x → 0 x x 4 + 4 x 2 + 5 = k ⇒ 0 0 + 4 × 0 + 5 = k ⇒ k = 0 Now solving lim x → 0 x 4 sin 1 3 x = l ⇒ 0 × sin ∞ = l ⇒ 0 × finite value = l ⇒ l = 0 Then k + l = 0