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AP EAMCET201922 Apr 2019Morning ShiftMathematicsLimitsActual

For (A 0, x < 0, _ n x-e^ n x 1+A e^ n x = )

Options

  1. A( 1 A )
  2. B( x )
  3. C(- 1 A )
  4. D(- x )

Correct answer

C. (- 1 A )

Step-by-step solution

Given, ( _ n x-e^ n x 1+A e^ n x = _ n e^ n x ( x e^ n x -1 ) e^ n x ( 1 e^ n x +A ) ) (= _ n x e^ n x -1 1 e^ n x +A = 0-1 0+A =- 1 A )

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