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AP EAMCET201922 Apr 2019Morning ShiftMathematicsLimitsActual

( _ n 1 n+m + 1 n+2 m + 1 n+3 m + + 1 n+n m = )

Options

  1. A( ₈(m) m )
  2. B( _e(1+m) 1+m )
  3. C( _e(1+m) m )
  4. D( _e(1+m) 1-m )

Correct answer

C. ( _e(1+m) m )

Step-by-step solution

Given, ( aligned & = _ n 1 n ( _ k=1 ^n 1 1+m ( k n ) ) & = ₀^1 1 1+m x d x= 1 m ₀^1 m 1+m x d x & = 1 m [ _e(1+m x) ]₀^1= 1 m [ _e(1+m)- (1) ] & = _e(1+m) m aligned )

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