AP EAMCET201922 Apr 2019Morning ShiftMathematicsLimitsActual
( _ n 1 n+m + 1 n+2 m + 1 n+3 m + + 1 n+n m = )
Options
- A( ₈(m) m )
- B( _e(1+m) 1+m )
- C( _e(1+m) m )
- D( _e(1+m) 1-m )
Correct answer
C. ( _e(1+m) m )
Step-by-step solution
Given, ( aligned & = _ n 1 n ( _ k=1 ^n 1 1+m ( k n ) ) & = ₀^1 1 1+m x d x= 1 m ₀^1 m 1+m x d x & = 1 m [ _e(1+m x) ]₀^1= 1 m [ _e(1+m)- (1) ] & = _e(1+m) m aligned )