Quantrex Quantrex AcademyJEE · NEET · NDA PYQs with solutions Open app
AP EAMCET201825 Apr 2018Morning ShiftMathematicsLimitsActual

If f : [ 0 , 2 ) → ℝ is defined by f x = 1 + 2 x k for 0 ≤ x < 1 k x for 1 ≤ x < 2 , where k > 0 and f is such that lim x → 1 - f x = lim x → 1 + f x , then the value of k 2 is

Options

  1. A2
  2. B1
  3. C4
  4. D1 4

Correct answer

C. 4

Step-by-step solution

Given: f x = 1 + 2 x k  for  0 ≤ x < 1 k x  for  1 ≤ x < 2 Now, lim x → 1 - f x = lim x → 1 + f x ⇒ 1 + 2 k = k ⇒ k + 2 = k 2 ⇒ k 2 - k - 2 = 0 ⇒ k 2 - 2 k + k - 2 = 0 ⇒ k + 1 k - 2 = 0 ⇒ k = 2   and   - 1 But, k > 0 Hence, k = 2 ⇒ k 2 = 4 .

Practice Limits on Quantrex Academy →

More from Limits

If _ x 0 ( p 2x + 1 - 2x x + x ) = 1 then the value of ' p ' is 2026_ x 2 ( 1 - x x ) is equal to 2026The value of _ x 3 [ 1 x-3 + 9x 27-x^3 ] is: 2026_ x 0 (1 - 2x)(3 + x) x 4x is equal to: 2026If _ x 3 ( x^2 - ax - 3b x - 3 ) = 5 , then a + b = 2026If f(x) = cases x^2 - 1 & if x 2 x + 1 & if x < 2 cases , then _ x 1 f(x) + _ x 2 f(x) = 2026_ x 4 2 2 -( x+ x)^3 1- 2 x = 2025Let [x] denote the greatest integer less than or equal to x . Then _ x 2⁺ ( [x]^3 3 - [ x 3 ]^3 )= 2025 Full Limits list All AP EAMCET PYQs