AP EAMCET2006MathematicsLimits
If 0 < p < q , then _ n (q^n+p^n )^ 1 / n is equal to :
Options
- Ae
- Bp
- Cq
- D0
Correct answer
C. q
Step-by-step solution
_ n (q^n+p^n )^ 1 / n =q _ n [1+ ( p q )^n ]^ 1 / n = _ n q [ 1+ ( p q )^n ^ (q / p)^n ]^ 1 / n ( p q )^n =q e^0 [ ( p q )^n 0 . as .n ]=q