AP EAMCET202319 May 2023Morning ShiftMathematicsMatricesActual
If A= [ array cccc 2 & 1 & 3 & -1 1 & -2 & 2 & -3 array ], B= [ array cccc 2 & 1 & 0 & 3 1 & -1 & 2 & 3 array ] and 2 ~A +3 ~B -5 C =0 , then C =
Options
- A[ array cccc 2 & 1 & 6 / 5 & 7 / 5 1 & 7 / 5 & 2 & 3 / 5 array ]
- B[ array cccc -2 & 1 & 6 / 5 & 7 / 5 1 & -7 / 5 & 2 & 3 / 5 array ]
- C[ array cccc -2 & 1 & 6 / 5 & 7 / 5 1 & 7 / 5 & 2 & 3 / 5 array ]
- D[ array cccc 2 & 1 & 6 / 5 & 7 / 5 1 & -7 / 5 & 2 & 3 / 5 array ]
Correct answer
D. [ array cccc 2 & 1 & 6 / 5 & 7 / 5 1 & -7 / 5 & 2 & 3 / 5 array ]
Step-by-step solution
aligned & Since 2 ~A +3 ~B -5 C =0 & 5 C =2 ~A +3 ~B & 5 C =2 [ array llll 2 & 1 & 3 & -1 1 & -2 & 2 & -3 array ]+3 [ array llll 2 & 1 & 0 & 3 1 & -1 & 2 & 3 array ] & 5 C = [ array cccc 4+6 & 2+3 & 6+0 & -2+9 2+3 & -4-3 & 4+6 & -6+9 array ] & 5 C = [ array cccc 10 & 5 & 6 & 7 5 & -7 & 10 & 3 array ] & aligned C= [ array cccc 2 & 1 & 6 / 5 & 7 / 5 1 & -7 / 5 & 2 & 3 / 5 array ]