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AIIMS 201826 May
Exam
AIIMS
Year
2018
Date
26 May
Subject
Chemistry
Chapter
Some Basic Concepts of Chemistry

AIIMS 2018 · 26 May · Chemistry · Some Basic Concepts of Chemistry

The normality of 10 \% H_2 SO_4 solution having density 1.1 ~g / cc...

The normality of 10%H2SO410 \% \mathrm{H}_2 \mathrm{SO}_4 solution having density 1.1 g/cc1.1 \mathrm{~g} / \mathrm{cc} is

Options

  1. A2.05 N2.05 \mathrm{~N}
  2. B1.25 N1.25 \mathrm{~N}
  3. C3.45 N3.45 \mathrm{~N}
  4. D2.24 N2.24 \mathrm{~N}

Correct answer

D. 2.24 N2.24 \mathrm{~N}

Step-by-step solution

Weight of H2SO4=10 g\mathrm{H}_2 \mathrm{SO}_4=10 \mathrm{~g} Weight of solution =100 g=100 \mathrm{~g} Volume of solution = Mass of solution  Density of solution =1001.1=90.91 mL\begin{aligned} \text{ Volume of solution } & =\frac{\text{ Mass of solution }}{\text{ Density of solution }} \\ & =\frac{100}{1.1}=90.91 \mathrm{~mL}\end{aligned} Normality =nH2SO4×1000 Volume of solution (in mL) =wH2SO4×1000GEMH2SO4× Volume of solution (in mL) \begin{aligned} & \text{ Normality }=\frac{n_{\mathrm{H}_2 \mathrm{SO}_4} \times 1000}{\text{ Volume of solution (in mL) }} \\ & =\frac{w_{\mathrm{H}_2 \mathrm{SO}_4} \times 1000}{\mathrm{GEM}_{\mathrm{H}_2 \mathrm{SO}_4} \times \text{ Volume of solution (in mL) }}\end{aligned}=10×1000(982)×90.91=2.24 N=\frac{10 \times 1000}{\left(\frac{98}{2}\right) \times 90.91}=2.24 \mathrm{~N}
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