AP EAMCET202124 Aug 2021Morning ShiftMathematicsMatricesActual
Let A= [ array ccc 1 & -1 & 2 0 & 3 & 4 array ], B= [ array ccc 4 & 0 & -3 -1 & -2 & -3 array ] and C= [ array cccc 2 & -3 & 0 & 1 5 & -1 & -4 & 2 -1 & 0 & 0 & 3 array ] , what is A^T B ?
Options
- A[ array ccc 4 & 0 & -3 -7 & -6 & -6 4 & -8 & -18 array ]
- BA^ B is not defined
- C[ array ccc 4 & -7 & 4 0 & -6 & -8 -3 & 12 & 6 array ]
- DA^T B=0
Correct answer
A. [ array ccc 4 & 0 & -3 -7 & -6 & -6 4 & -8 & -18 array ]
Step-by-step solution
A= [ array ccc 1 & -1 & 2 0 & 3 & 4 array ], B= [ array ccc 4 & 0 & -3 -1 & -2 & -3 array ] and C= [ array cccc 2 & -3 & 0 & 1 5 & -1 & -4 & 2 -1 & 0 & 0 & 3 array ] Now, A^T= [ array cc 1 & 0 -1 & 3 2 & 4 array ], B= [ array ccc 4 & 0 & -3 -1 & -2 & -3 array ] A^T B= [ array cc 1 & 0 -1 & 3 2 & 4 array ] [ array ccc 4 & 0 & -3 -1 & -2 & -3 array ]= [ array ccc 4+0 & 0+0 & -3+0 -4-3 & 0-6 & 3-9 8-4 & 0-8 & -6-12 array ]= [ array ccc 4 & 0 & -3 -7 & -6 & -6 4 & -8 & -18 array ]